If a cylinder has actually a massive of 18.426g, a diameter that 1.34cm, and a elevation of 6.48cm, what is the thickness of the cylinder?
Density is exactly how much massive is in a given volume (ρ = m / v).
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The mass of the object is given, 18.426 g.
The next thing we should do is discover the volume the the cylinder. V = π * (d / 2)2 * h
So if us plug whatever in, us get: V = (3.14159) * (1.34 / 2)2 * 6.48 = 9.138 cm3
Then, us plug ours mass and volume into this formula: ρ = m / v
Once we plug every little thing in, us get: ρ = (18.426 / 9.138) = 2.02 g/cm3
Density = 2.02 g/cm3
Density if the mass divided by the volume. The volume of a cylinder is the area of the basic (which is a circle so the is πr2) times the height. In this case, we have been offered the diameter for this reason we have to divide that by 2 to gain the radius (r). So, if the diameter is 1.34, climate the radius is 1.34/2 = 0.67 cm then we would certainly calculate the volume choose this:
V = πr2•h
V = π(0.67)2•(6.48)
V = 9.138490905 cm3
The thickness then calculated prefer this:
D = M/V
D = (18.426 g)/(9.138490905 cm3)
D = 2.016306652 g/cm3 however, we should round come the appropriate significant figure. The smallest sig fig the numbers provided is 3 (both 1.34 cm and 6.48 cm have actually 3 sig figs) for this reason our answer should have actually 3 sig figs.
So D = 2.02 g/cm3
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