You are watching: V = pi * r ^ 2 * h
0 ext and also V eq 0\h eq 0 ext, &V=0 ext and r=0endmatrix ight.$" role="text" class="MathExpression_mathExpression__22QI1 MathExpression_scrollable__2WXwu">
how do you create the facility number in trigonometric type displaystylefrac52left(sqrt3-i ight) ?
In trigonometric type expressed asdisplaystyle5left(cos330+isin330 ight) Explanation: displaystyleZ=a+ib . Modulus:displaystyle=sqrta^2+b^2 ...
detect volume that a solid over region E, bounded listed below by cone z = sqrtx^2 + y^2 and over by sphere z^2 = 1- x^2 - y^2
The an ar E in cylindrical coordinate is offered by E = left(r, heta,z)colon 0le rle 1/sqrt2, 0le hetale 2pi, rle zle sqrt1-r^2 ight. To check out this, observe that z is ...
Find facility of one of radius r that overlaps specifically lfloor pi r^2 ceil point out of the creature grid
that is always possible. Here is a nonconstructive proof. Deal with r. Because that any suggest z in mathbbR^2, permit f(z) be the number of lattice points within a bowl of radius r centered at z. (Make ...
The duty has poles in ~ ;z=pm1,,,,frac i2; , therefore the maximal convergence radius that convergence roughly ;z=1; cannot be better than left|1-frac12i ight|=sqrt1+frac14=fracsqrt52 ...
What is the relation in between orbital velocity and also escape velocity in strongly relativistic situations?
because that a static black hole defined by the Schwarzschild metric the escape velocity is: v_e = cleft(1 - fracr_sr ight)sqrtfracr_sr ag1 and also the orbital velocity is: v_o = csqrtfracr_s2(r - r_s) ag2 ...
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The very first integral is same to, in the limit together R o infty, e^i pi int_infty^0 fracdxe^i pi/2 sqrtx (1+x^2) + int_0^infty fracdxsqrtx (1+x^2) = (1-i) int_0^infty fracdxsqrtx (1+x^2) ...
left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray together l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>
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