Ethanol, C2H5OH burns v oxygen in waiting to provide carbon dioxide and water. What is the amount (in moles) the water created from 0.51 mol C2H5OH? The equation is C2H5OH + 3O2 -----> 2CO2 + 3H2O.
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This is an example of a combustion reaction. To answer this friend must an initial balance the equation.

The easiest means is to collection up the reaction equation without any kind of coefficients:

C2H6O + O2 --> CO2 + HOH

Now start balancing, very first with carbon, then v hydrogen and also last the oxygen.

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This is an example of a burning reaction. Come answer this friend must very first balance the equation.

The easiest way is to set up the reaction equation without any kind of coefficients:

C2H6O + O2 --> CO2 + HOH

Now start balancing, an initial with carbon, then with hydrogen and also last the oxygen.

There space 2 carbons ~ above the left and 6 hydrogens so you include a coefficient that 2 in former of the CO2 and also a 3 in front of the water.

C2H6O + O2 --> 2 CO2 + 3 HOH

Now counting the variety of oxygen ~ above the product side and also you get seven. One oxygen came from the ethanol for this reason you require 6 more from oxygen. Add a coefficient of 3 in front of the oxygen ~ above the reactant side and your reaction is balanced.

C2H60 + 3 O2 --> 2 CO2 + 3 HOH

This shows you that for every mole of ethanol, you will acquire 3 moles of water. So if you start with 0.51 moles of ethanol, you will produce 3 x .51 or 1.53 mole of water.

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