lifwynnfoundation.org"s solved instance with systems to uncover what is the probability of getting 2 top in 5 coin tosses. P(A) = 26/32 = 0.81

for 2 top in 5 Coin FlipsAtleast 2 HeadsExactly 2 Heads

Total occasions n(S) | 32 | 32 |

Success events n(A) | 26 | 10 |

Probability P(A) | 0.81 | 0.31 |

The above probability the outcomes applicable come the below questions too.

Probability of flipping a coin 2 times and getting 5 heads in a row Probability of gaining 5 heads when flipping 2 coins with each other A coin is tossed 2 times, find the probability that at the very least 5 are heads? If you upper and lower reversal a fair coin 2 times what is the probability that you will get exactly 5 heads? A coin is tossed 2 times, what is the probability the getting precisely 5 heads?

The ratio of successful events A = 26 come the total variety of possible combinations of a sample an are S = 32 is the probability the 2 top in 5 coin tosses. Users might refer the below solved example work with actions to learn just how to discover what is the probability of gaining at-least 2 heads, if a coin is tossed 5 times or 5 coins tossed together. Users may refer this tree diagram to learn just how to discover all the possible combinations that sample room for flipping a coin one, two, three or 4 times.

You are watching: Toss a coin 5 times. what is the probability of getting exactly 2 tails?

**Solution**Step by step workoutstep 1 uncover the total possible events that sample space S S = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT S = 32 step 2 discover the intended or successful occasions A A = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, TTHHH, TTHHT, TTHTH, TTTHH A = 26 action 3 discover the probability P(A) = effective Events/Total events of Sample room = 26/32 = 0.81 P(A) = 0.81 0.81 is the probability of gaining 2 heads in 5 tosses.

The ratio of successful occasions A = 10 to total variety of possible combine of sample space S = 32 is the probability the 2 top in 5 coin tosses. Users might refer the listed below detailed solved example with step by action calculation come learn just how to discover what is the probability that getting precisely 2 heads, if a coin is tossed 5 times or 5 coins tossed together.

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**Solution :**action by step workout step 1 uncover the total possible combinations the sample space S S = HHHHH, HHHHT, HHHTH, HHHTT, HHTHH, HHTHT, HHTTH, HHTTT, HTHHH, HTHHT, HTHTH, HTHTT, HTTHH, HTTHT, HTTTH, HTTTT, THHHH, THHHT, THHTH, THHTT, THTHH, THTHT, THTTH, THTTT, TTHHH, TTHHT, TTHTH, TTHTT, TTTHH, TTTHT, TTTTH, TTTTT S = 32 step 2 find the intended or successful occasions A A = HHTTT, HTHTT, HTTHT, HTTTH, THHTT, THTHT, THTTH, TTHHT, TTHTH, TTTHH A = 10 step 3 uncover the probability P(A) = effective Events/Total occasions of Sample room = 10/32 = 0.31 P(A) = 0.31 0.31 is the probability of getting exactly 2 top in 5 tosses.